Combination Clipper
Operation of a Combination Clipper:
During the positive half cycle, if the input voltage is greater than +V1, the diode D1 conducts and becomes a short while the diode D2 is reverse biased and does not conduct.
The output voltage remains +V1 as long as the input voltage is greater than +V1.
When the input voltage then becomes less than +V1, the diode D1 becomes reverse biased, thereby being an open (ie no current passes through it), since the diode D2 is already reverse biased, the input voltage now appears across the load.
On the other hand, during the negative half cycle, if the input voltage is lesser than -V2 with respect to the polarity, the diode D2 conducts and becomes a short while the diode D1 is reverse biased and does not conduct.
The output voltage remains -V2 as long as the input voltage is lesser than -V2.
When the input voltage then becomes greater than -V2, the diode D2 becomes reverse biased and open, thereby not allowing current to pass through it, since the diode D1 is already reverse biased, the input voltage of the negative cycle now appears across the load.
Note that +V1 and -V2 each appears to be constant on the output voltage and the reason is because they are DC voltages (discrete) and not continuous like the AC signal.
On the other hand, during the negative half cycle, if the input voltage is lesser than -V2 with respect to the polarity, the diode D2 conducts and becomes a short while the diode D1 is reverse biased and does not conduct.
The output voltage remains -V2 as long as the input voltage is lesser than -V2.
When the input voltage then becomes greater than -V2, the diode D2 becomes reverse biased and open, thereby not allowing current to pass through it, since the diode D1 is already reverse biased, the input voltage of the negative cycle now appears across the load.
Note that +V1 and -V2 each appears to be constant on the output voltage and the reason is because they are DC voltages (discrete) and not continuous like the AC signal.
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